2x^2-3ix+1=0

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Solution for 2x^2-3ix+1=0 equation:


Simplifying
2x2 + -3ix + 1 = 0

Reorder the terms:
1 + -3ix + 2x2 = 0

Solving
1 + -3ix + 2x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -3ix + -1 + 2x2 = 0 + -1

Reorder the terms:
1 + -1 + -3ix + 2x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3ix + 2x2 = 0 + -1
-3ix + 2x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-3ix + 2x2 = -1

Add '-2x2' to each side of the equation.
-3ix + 2x2 + -2x2 = -1 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-3ix + 0 = -1 + -2x2
-3ix = -1 + -2x2

Divide each side by '-3x'.
i = 0.3333333333x-1 + 0.6666666667x

Simplifying
i = 0.3333333333x-1 + 0.6666666667x

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